What is the solution for (x^2+y^2)dx=xydy ?

The solution for (x^2+y^2)dx=xydy is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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(x^2+y^2)dx=xydy

(x^{2} + y^{2}) d x = x y d y

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

(x^{2} + y^{2}) d x = x y d y

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

\frac{d}{d x} ((\frac{4 x ^{2}}{4 - x})^{3})

\int (4 x^{3}) d x

\int_{1}^{3} arctan (x) d x

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f (x) = x (x - 4)

What is the solution for (x^2+y^2)dx=xydy ?
The solution for (x^2+y^2)dx=xydy is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}