What is the derivative of x^2+4/x ?

The derivative of x^2+4/x is 2x-4/(x^2)

What is the first derivative of x^2+4/x ?

The first derivative of x^2+4/x is 2x-4/(x^2)

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\frac{d}{d x} (x^{2} + \frac{4}{x})

2 x - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 2 x - \frac{4}{x ^{2}}

\frac{\partial}{\partial x} (ln (3 x + 3 cy))

cos (5 π x)

\frac{5 - x ^{2}}{5 + x ^{2}}

\int 7 x^{2} ln (x) d x

\frac{d y}{d x}, arctan (x y) = arcsin (4 x + 4 y), (0, 0)

What is the derivative of x^2+4/x ?
The derivative of x^2+4/x is 2x-4/(x^2)
What is the first derivative of x^2+4/x ?
The first derivative of x^2+4/x is 2x-4/(x^2)