What is the derivative of sin(4x^2+3x) ?

The derivative of sin(4x^2+3x) is cos(4x^2+3x)(8x+3)

What is the first derivative of sin(4x^2+3x) ?

The first derivative of sin(4x^2+3x) is cos(4x^2+3x)(8x+3)

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\frac{d}{d x} (sin (4 x^{2} + 3 x))

cos (4 x^{2} + 3 x) (8 x + 3)

Solution steps

\frac{d}{d x} (sin (4 x^{2} + 3 x))

Apply the chain rule:

cos (4 x^{2} + 3 x) \frac{d}{d x} (4 x^{2} + 3 x)

= cos (4 x^{2} + 3 x) \frac{d}{d x} (4 x^{2} + 3 x)

\frac{d}{d x} (4 x^{2} + 3 x) = 8 x + 3

= cos (4 x^{2} + 3 x) (8 x + 3)

\int \frac{8}{x 64 - ( ln ( x ) ) ^{2}} d x

\int sec^{6} (5 x) tan (5 x) d x

(1 - x^{2})^{^{'}}

y^{^{'}} + x y + 4 = 0

\int \frac{1}{x ^{2} - 36} d x

What is the derivative of sin(4x^2+3x) ?
The derivative of sin(4x^2+3x) is cos(4x^2+3x)(8x+3)
What is the first derivative of sin(4x^2+3x) ?
The first derivative of sin(4x^2+3x) is cos(4x^2+3x)(8x+3)