What is the derivative of sin(x+pi) ?

The derivative of sin(x+pi) is -cos(x)

What is the first derivative of sin(x+pi) ?

The first derivative of sin(x+pi) is -cos(x)

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\frac{d}{d x} (sin (x + π))

- cos (x)

Solution steps

\frac{d}{d x} (sin (x + π))

Simplify

sin (x + π) : - sin (x)

= \frac{d}{d x} (- sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (x))

Apply the common derivative:

\frac{d}{d x} (sin (x)) = cos (x)

= - cos (x)

x^{2} e^{x}

n = 0 \sum \infty tan (n)

\int \frac{csc ^{2} ( 2 x )}{cot ^{5} ( 2 x )} d x

x \to 1 lim (\frac{8 x + 1}{x + 3})

\int (e^{3 x}) d x

What is the derivative of sin(x+pi) ?
The derivative of sin(x+pi) is -cos(x)
What is the first derivative of sin(x+pi) ?
The first derivative of sin(x+pi) is -cos(x)