What is the derivative of x^4-32x^2 ?

The derivative of x^4-32x^2 is 4x^3-64x

What is the first derivative of x^4-32x^2 ?

The first derivative of x^4-32x^2 is 4x^3-64x

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\frac{d}{d x} (x^{4} - 32 x^{2})

4 x^{3} - 64 x

Solution steps

\frac{d}{d x} (x^{4} - 32 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (32 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (32 x^{2}) = 64 x

= 4 x^{3} - 64 x

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 3, y^{^{'}} (0) = - 1

x \to 2 lim (4 x^{2} - 8 x)

\frac{d}{d x} (\frac{e ^{6 x}}{x})

x \to 3 lim (x + 3)

- \frac{18}{x ^{3}}

What is the derivative of x^4-32x^2 ?
The derivative of x^4-32x^2 is 4x^3-64x
What is the first derivative of x^4-32x^2 ?
The first derivative of x^4-32x^2 is 4x^3-64x