What is the derivative of tan(1+e^{2x}) ?

The derivative of tan(1+e^{2x}) is sec^2(1+e^{2x})*2e^{2x}

What is the first derivative of tan(1+e^{2x}) ?

The first derivative of tan(1+e^{2x}) is sec^2(1+e^{2x})*2e^{2x}

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\frac{d}{d x} (tan (1 + e^{2 x}))

sec^{2} (1 + e^{2 x}) \cdot 2 e^{2 x}

Solution steps

\frac{d}{d x} (tan (1 + e^{2 x}))

Apply the chain rule:

sec^{2} (1 + e^{2 x}) \frac{d}{d x} (1 + e^{2 x})

= sec^{2} (1 + e^{2 x}) \frac{d}{d x} (1 + e^{2 x})

\frac{d}{d x} (1 + e^{2 x}) = 2 e^{2 x}

= sec^{2} (1 + e^{2 x}) \cdot 2 e^{2 x}

- 2 lo g_{e} (x) + x^{2} - 4 + e^{x} + x^{e}

\int 2 csc^{4} (x) cot^{6} (x) d x

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What is the derivative of tan(1+e^{2x}) ?
The derivative of tan(1+e^{2x}) is sec^2(1+e^{2x})*2e^{2x}
What is the first derivative of tan(1+e^{2x}) ?
The first derivative of tan(1+e^{2x}) is sec^2(1+e^{2x})*2e^{2x}