What is the tangent of f(x)=x^2-2x-6,\at x=-2 ?

The tangent of f(x)=x^2-2x-6,\at x=-2 is y=-6x-10

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tangent of f(x)=x^2-2x-6,\at x=-2

tangent of

f (x) = x^{2} - 2 x - 6, at x = - 2

y = - 6 x - 10

Solution steps

Find the tangent point:

(- 2, 2)

Find the slope of

f (x) = x^{2} - 2 x - 6 : \frac{df ( x )}{d x} = 2 x - 2

Compute the slope of

f (x) = x^{2} - 2 x - 6

x = - 2 : m = - 6

Find the line with slope m=

- 6

and passing through

(- 2, 2) : y = - 6 x - 10

y = - 6 x - 10

x \to 8 lim (\frac{4}{x - 8})

\int_{0}^{6} 15 4 x + 1 d x

\frac{d}{d x} (\frac{- 2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}})

\frac{d}{d x} (\frac{2 arcsin ( x )}{1 - x ^{2}})

\int x^{4} (x^{5} + 1)^{18} d x

What is the tangent of f(x)=x^2-2x-6,\at x=-2 ?
The tangent of f(x)=x^2-2x-6,\at x=-2 is y=-6x-10