What is the derivative of y=ln(ln(2x)) ?

The derivative of y=ln(ln(2x)) is 1/(xln(2x))

What is the first derivative of y=ln(ln(2x)) ?

The first derivative of y=ln(ln(2x)) is 1/(xln(2x))

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derivative of

y = ln (ln (2 x))

\frac{1}{x ln ( 2 x )}

Solution steps

\frac{d}{d x} (ln (ln (2 x)))

Apply the chain rule:

\frac{1}{ln ( 2 x )} \frac{d}{d x} (ln (2 x))

= \frac{1}{ln ( 2 x )} \frac{d}{d x} (ln (2 x))

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

= \frac{1}{ln ( 2 x )} \cdot \frac{1}{x}

Simplify

\frac{1}{ln ( 2 x )} \cdot \frac{1}{x} : \frac{1}{x ln ( 2 x )}

= \frac{1}{x ln ( 2 x )}

\frac{d}{d t} (sin (wt))

\frac{1}{s ^{3} + 6 s}

\frac{d y}{d x} = \frac{x y + x ^{2} e ^{\frac{y}{x}}}{x ^{2}}

\int - 20

2 y^{^{'}} + y = \frac{e ^{2 x}}{2}

What is the derivative of y=ln(ln(2x)) ?
The derivative of y=ln(ln(2x)) is 1/(xln(2x))
What is the first derivative of y=ln(ln(2x)) ?
The first derivative of y=ln(ln(2x)) is 1/(xln(2x))