What is the sum from n=1 to infinity of (n/(n+1))^n ?

The sum from n=1 to infinity of (n/(n+1))^n is diverges

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sum from n=1 to infinity of (n/(n+1))^n

n = 1 \sum \infty (\frac{n}{n + 1})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{n}{n + 1})^{n}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of (n/(n+1))^n ?
The sum from n=1 to infinity of (n/(n+1))^n is diverges