What is the d/(dθ)(3tan(θ)) ?

The d/(dθ)(3tan(θ)) is 3sec^2(θ)

What is the first d/(dθ)(3tan(θ)) ?

The first d/(dθ)(3tan(θ)) is 3sec^2(θ)

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\frac{d}{d θ} (3 tan (θ))

3 sec^{2} (θ)

Solution steps

\frac{d}{d θ} (3 tan (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d θ} (tan (θ))

Apply the common derivative:

\frac{d}{d θ} (tan (θ)) = sec^{2} (θ)

= 3 sec^{2} (θ)

n = 1 \sum \infty a^{n - 1} \cdot n

\int sin (x + 5) d x

\int 3 x^{2} - 2 x + 5 d x

\int k t d t

x \to 0 lim (\frac{e ^{x}}{x ^{2} - x})