What is the limit as x approaches 1 of x^{5/(x^2-1)} ?

The limit as x approaches 1 of x^{5/(x^2-1)} is e^{5/2}

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limit as x approaches 1 of x^{5/(x^2-1)}

x \to 1 lim (x^{\frac{5}{x ^{2} - 1}})

e^{\frac{5}{2}}

Decimal Notation

12.18249 \dots

Solution steps

x \to 1 lim (x^{\frac{5}{x ^{2} - 1}})

Apply exponent rules

= x \to 1 lim (e^{\frac{5}{x ^{2} - 1} l n (x)})

Apply the Limit Chain Rule:

e^{\frac{5}{2}}

= e^{\frac{5}{2}}

f (x) = x arcsin (x)

\frac{d}{d x} (\frac{6 x + 5}{7 - 3 x ^{2}})

\int_{0}^{2 π} (1 + sin (u)) d u

y^{^{''}} = 5 y

\int_{a}^{b} 1 d x

What is the limit as x approaches 1 of x^{5/(x^2-1)} ?
The limit as x approaches 1 of x^{5/(x^2-1)} is e^{5/2}