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Popular >

area y=x^2,y=4x-x^2

Solution

area

y = x^{2}, y = 4 x - x^{2}

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} - (4 x - x^{2}) d x

Solve

\int_{0}^{2} x^{2} - (4 x - x^{2}) d x : \frac{8}{3}

The area is:

= \frac{8}{3}

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\int_{0}^{4} \frac{1}{x} d x

limit as x approaches infinity of 3x-4

x \to \infty lim (3 x - 4)

(2dy)/(dx)-4xy=8x

\frac{2 d y}{d x} - 4 x y = 8 x

integral of sqrt(x^6-x^8)

\int x^{6} - x^{8} d x

Frequently Asked Questions (FAQ)

What is area y=x^2,y=4x-x^2 ?
The answer to area y=x^2,y=4x-x^2 is 8/3