What is the derivative of (x^2+4)^7 ?

The derivative of (x^2+4)^7 is 14x(x^2+4)^6

What is the first derivative of (x^2+4)^7 ?

The first derivative of (x^2+4)^7 is 14x(x^2+4)^6

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derivative of

(x^{2} + 4)^{7}

14 x (x^{2} + 4)^{6}

Solution steps

\frac{d}{d x} ((x^{2} + 4)^{7})

Apply the chain rule:

7 (x^{2} + 4)^{6} \frac{d}{d x} (x^{2} + 4)

= 7 (x^{2} + 4)^{6} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= 7 (x^{2} + 4)^{6} \cdot 2 x

Simplify

= 14 x (x^{2} + 4)^{6}

x \to a lim (2 - x)

y^{^{''}} - 6 y^{^{'}} + 9 y = 24 - 9 t - (12 t e^{3 t} + 4 e^{3 t})

x \to 4 - lim (x)

d x + (x + y + 1) d y = 0

f (x) = x^{3} - x - 1

What is the derivative of (x^2+4)^7 ?
The derivative of (x^2+4)^7 is 14x(x^2+4)^6
What is the first derivative of (x^2+4)^7 ?
The first derivative of (x^2+4)^7 is 14x(x^2+4)^6