What is the integral from 2 to infinity of 2/(t^2-1) ?

The integral from 2 to infinity of 2/(t^2-1) is ln(3)

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integral from 2 to infinity of 2/(t^2-1)

\int_{2}^{\infty} \frac{2}{t ^{2} - 1} d t

ln (3)

Decimal Notation

1.09861 \dots

Solution steps

\int_{2}^{\infty} \frac{2}{t ^{2} - 1} d t

Compute the indefinite integral:

\int \frac{2}{t ^{2} - 1} d t = - ln ∣ t + 1 ∣ + ln ∣ t - 1 ∣ + C

Compute the boundaries:

\int_{2}^{\infty} \frac{2}{t ^{2} - 1} d t = 0 - (- ln (3))

= 0 - (- ln (3))

Simplify

= ln (3)

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What is the integral from 2 to infinity of 2/(t^2-1) ?
The integral from 2 to infinity of 2/(t^2-1) is ln(3)