What is the sum from n=0 to infinity}(5^{2n of)/(n!) ?

The sum from n=0 to infinity}(5^{2n of)/(n!) is converges

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sum from n=0 to infinity}(5^{2n of)/(n!)

n = 0 \sum \infty \frac{5 ^{2 n}}{n !}

converges

Solution steps

n = 0 \sum \infty \frac{5 ^{2 n}}{n !}

Apply Series Ratio Test:

converges

= converges

8 - x^{2}

\int 8 cos^{2} (5 x) d x

\frac{d}{d x} (\frac{5 ^{x} + 2}{5 ^{x} + 1})

y = - 8 + 5 x

\int \frac{14}{1 - cos ( 2 x )} d x

What is the sum from n=0 to infinity}(5^{2n of)/(n!) ?
The sum from n=0 to infinity}(5^{2n of)/(n!) is converges