What is inverse oflaplace 4/(s+4) ?

The answer to inverse oflaplace 4/(s+4) is 4e^{-4t}

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inverse oflaplace 4/(s+4)

inverse laplace

\frac{4}{s + 4}

4 e^{- 4 t}

Solution steps

L^{- 1} {\frac{4}{s + 4}}

= L^{- 1} {4 \cdot \frac{1}{s + 4}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 4}} = e^{- 4 t}

= 4 e^{- 4 t}

\frac{d}{d x} (x - (\frac{x}{2})^{2} + (\frac{x}{3})^{3})

ln (ln (5 x))

x \to \infty lim ((1 + \frac{3}{x})^{\frac{x}{4}})

h (x) = ln (x + x^{2} - 7)

\frac{- 2 s + 1}{s ^{2} + 2 s - 8}

What is inverse oflaplace 4/(s+4) ?
The answer to inverse oflaplace 4/(s+4) is 4e^{-4t}