What is the derivative of (1/(y^2)-3/(y^4))(y+9y^3) ?

The derivative of (1/(y^2)-3/(y^4))(y+9y^3) is (26)/(y^2)+9/(y^4)+9

What is the first derivative of (1/(y^2)-3/(y^4))(y+9y^3) ?

The first derivative of (1/(y^2)-3/(y^4))(y+9y^3) is (26)/(y^2)+9/(y^4)+9

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derivative of

(\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 9 y^{3})

\frac{26}{y ^{2}} + \frac{9}{y ^{4}} + 9

Solution steps

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 9 y^{3}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{y ^{2}} - \frac{3}{y ^{4}}, g = y + 9 y^{3}

= \frac{d}{d y} (\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 9 y^{3}) + \frac{d}{d y} (y + 9 y^{3}) (\frac{1}{y ^{2}} - \frac{3}{y ^{4}})

\frac{d}{d y} (\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) = - \frac{2}{y ^{3}} + \frac{12}{y ^{5}}

\frac{d}{d y} (y + 9 y^{3}) = 1 + 27 y^{2}

= (- \frac{2}{y ^{3}} + \frac{12}{y ^{5}}) (y + 9 y^{3}) + (1 + 27 y^{2}) (\frac{1}{y ^{2}} - \frac{3}{y ^{4}})

Simplify

(- \frac{2}{y ^{3}} + \frac{12}{y ^{5}}) (y + 9 y^{3}) + (1 + 27 y^{2}) (\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) : \frac{26}{y ^{2}} + \frac{9}{y ^{4}} + 9

= \frac{26}{y ^{2}} + \frac{9}{y ^{4}} + 9

h \to 0 lim (\frac{( x + h ) ^{2} - 9}{h})

x^{3}, - x, 1

n = 0 \sum \infty cos (\frac{1}{n})

x \to 0 lim (4 - ln (x))

\int (5 cos (x) - 3 sin (x)) d x

What is the derivative of (1/(y^2)-3/(y^4))(y+9y^3) ?
The derivative of (1/(y^2)-3/(y^4))(y+9y^3) is (26)/(y^2)+9/(y^4)+9
What is the first derivative of (1/(y^2)-3/(y^4))(y+9y^3) ?
The first derivative of (1/(y^2)-3/(y^4))(y+9y^3) is (26)/(y^2)+9/(y^4)+9