What is the derivative of-16x^2+64x ?

The derivative of-16x^2+64x is -32x+64

What is the first derivative of-16x^2+64x ?

The first derivative of-16x^2+64x is -32x+64

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\frac{d}{d x} (- 16 x^{2} + 64 x)

- 32 x + 64

Solution steps

\frac{d}{d x} (- 16 x^{2} + 64 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (16 x^{2}) + \frac{d}{d x} (64 x)

\frac{d}{d x} (16 x^{2}) = 32 x

\frac{d}{d x} (64 x) = 64

= - 32 x + 64

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What is the derivative of-16x^2+64x ?
The derivative of-16x^2+64x is -32x+64
What is the first derivative of-16x^2+64x ?
The first derivative of-16x^2+64x is -32x+64