What is the derivative of (2x^6+5x^3^{3/5}) ?

The derivative of (2x^6+5x^3^{3/5}) is (3(12x^5+15x^2))/(5(2x^6+5x^3)^{2/5)}

What is the first derivative of (2x^6+5x^3^{3/5}) ?

The first derivative of (2x^6+5x^3^{3/5}) is (3(12x^5+15x^2))/(5(2x^6+5x^3)^{2/5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((2 x^{6} + 5 x^{3})^{\frac{3}{5}})

\frac{3 ( 12 x ^{5} + 15 x ^{2} )}{5 ( 2 x ^{6} + 5 x ^{3} ) ^{\frac{2}{5}}}

Solution steps

\frac{d}{d x} ((2 x^{6} + 5 x^{3})^{\frac{3}{5}})

Apply the chain rule:

\frac{3}{5 ( 2 x ^{6} + 5 x ^{3} ) ^{\frac{2}{5}}} \frac{d}{d x} (2 x^{6} + 5 x^{3})

= \frac{3}{5 ( 2 x ^{6} + 5 x ^{3} ) ^{\frac{2}{5}}} \frac{d}{d x} (2 x^{6} + 5 x^{3})

\frac{d}{d x} (2 x^{6} + 5 x^{3}) = 12 x^{5} + 15 x^{2}

= \frac{3}{5 ( 2 x ^{6} + 5 x ^{3} ) ^{\frac{2}{5}}} (12 x^{5} + 15 x^{2})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ( 12 x ^{5} + 15 x ^{2} )}{5 ( 2 x ^{6} + 5 x ^{3} ) ^{\frac{2}{5}}}

n = 1 \sum \infty 1 + (\frac{1}{2})^{n}

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = x

x \to - \infty lim (\frac{7}{x} - 2)

\frac{\partial}{\partial x} (0.5 ln (x^{2} + y^{2}))

y = 5 x^{6} ln (x)

What is the derivative of (2x^6+5x^3^{3/5}) ?
The derivative of (2x^6+5x^3^{3/5}) is (3(12x^5+15x^2))/(5(2x^6+5x^3)^{2/5)}
What is the first derivative of (2x^6+5x^3^{3/5}) ?
The first derivative of (2x^6+5x^3^{3/5}) is (3(12x^5+15x^2))/(5(2x^6+5x^3)^{2/5)}