What is the derivative of 2/(t+1) ?

The derivative of 2/(t+1) is -2/((t+1)^2)

What is the first derivative of 2/(t+1) ?

The first derivative of 2/(t+1) is -2/((t+1)^2)

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derivative of

\frac{2}{t + 1}

- \frac{2}{( t + 1 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{2}{t + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (\frac{1}{t + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d t} ((t + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( t + 1 ) ^{2}} \frac{d}{d t} (t + 1)

= - \frac{1}{( t + 1 ) ^{2}} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= 2 (- \frac{1}{( t + 1 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( t + 1 ) ^{2}} \cdot 1) : - \frac{2}{( t + 1 ) ^{2}}

= - \frac{2}{( t + 1 ) ^{2}}

46 - \frac{x}{250}

\frac{12}{x ^{2} ( x - 3 )}

e^{x^{4}}

\int (4 x^{3} y^{2} - 2 x y^{3}) d x

\frac{d}{d x} (5^{s i n (3 x)})

What is the derivative of 2/(t+1) ?
The derivative of 2/(t+1) is -2/((t+1)^2)
What is the first derivative of 2/(t+1) ?
The first derivative of 2/(t+1) is -2/((t+1)^2)