What is the derivative of f(x)=6xe^x ?

The derivative of f(x)=6xe^x is 6(e^x+e^xx)

What is the first derivative of f(x)=6xe^x ?

The first derivative of f(x)=6xe^x is 6(e^x+e^xx)

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derivative of

f (x) = 6 x e^{x}

6 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (6 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 6 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 6 (1 \cdot e^{x} + e^{x} x)

Simplify

= 6 (e^{x} + e^{x} x)

\frac{d}{d x} ((x^{4} - 1) (x^{2} + 1))

\int (8 x^{5} - 8 x^{- 3}) d x

e^{x y}

\frac{10}{s ( s ^{2} + 10 s + 50 )}

x \to - 4 lim (6 x + 1)

What is the derivative of f(x)=6xe^x ?
The derivative of f(x)=6xe^x is 6(e^x+e^xx)
What is the first derivative of f(x)=6xe^x ?
The first derivative of f(x)=6xe^x is 6(e^x+e^xx)