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Popular >

(x+1)^'

Solution

(x + 1)^{^{'}}

Solution

1

Solution steps

(x + 1)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x^{^{'}} + 1^{^{'}}

x^{'} = 1

1^{'} = 0

= 1 + 0

Simplify

= 1

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x \to 1 lim (\frac{x ^{2} - 3 x}{x})

(2xy+y^4)dx+(3x^2+6xy^3)dy=0

(2 x y + y^{4}) d x + (3 x^{2} + 6 x y^{3}) d y = 0

y^'+4/5 y=1-1/4 t

y^{^{'}} + \frac{4}{5} y = 1 - \frac{1}{4} t

integral of 2/(sqrt(1-t^2))

\int \frac{2}{1 - t ^{2}} d t

Frequently Asked Questions (FAQ)

What is the (x+1)^' ?
The (x+1)^' is 1
What is the first (x+1)^' ?
The first (x+1)^' is 1