What is the derivative of 4sin(3t) ?

The derivative of 4sin(3t) is 12cos(3t)

What is the first derivative of 4sin(3t) ?

The first derivative of 4sin(3t) is 12cos(3t)

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derivative of

4 sin (3 t)

12 cos (3 t)

Solution steps

\frac{d}{d t} (4 sin (3 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (sin (3 t))

Apply the chain rule:

cos (3 t) \frac{d}{d t} (3 t)

= cos (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= 4 cos (3 t) \cdot 3

Simplify

= 12 cos (3 t)

\int (1 - x^{3} + 5 x^{5} - 3 x^{7}) d x

\frac{d}{d x} (80 π cos (10 π x))

\frac{\partial}{\partial x} (x^{6} + 5 x y^{9})

\frac{d}{d x} (\frac{8 x ^{3} - 2 x + 9}{x})

\frac{d}{d x} (\frac{1}{4 x ^{3} + 5 x ^{2} - 7 x + 8})

What is the derivative of 4sin(3t) ?
The derivative of 4sin(3t) is 12cos(3t)
What is the first derivative of 4sin(3t) ?
The first derivative of 4sin(3t) is 12cos(3t)