What is the (sin(t)-tcos(t))^' ?

The (sin(t)-tcos(t))^' is tsin(t)

What is the first (sin(t)-tcos(t))^' ?

The first (sin(t)-tcos(t))^' is tsin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin (t) - t cos (t))^{^{'}}

t sin (t)

Solution steps

(sin (t) - t cos (t))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (sin (t))^{^{'}} - (t cos (t))^{^{'}}

(sin (t))^{'} = cos (t)

(t cos (t))^{'} = cos (t) - t sin (t)

= cos (t) - (cos (t) - t sin (t))

Simplify

= t sin (t)

\frac{d}{d x} (\frac{4 x}{x + 5})

\frac{d}{d x} ((1 - 3 x)^{2} (x^{2} - 2)^{3})

\frac{\partial}{\partial y} (x y + x)

\frac{d y}{d x} + y = 2

x \to - 3 lim ([\frac{1}{2} x^{2} + 3])