What is (\partial)/(\partial x)(x^ab^b) ?

The answer to (\partial)/(\partial x)(x^ab^b) is b^bax^{a-1}

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(\partial)/(\partial x)(x^ab^b)

\frac{\partial}{\partial x} (x^{a} b^{b})

b^{b} a x^{a - 1}

Solution steps

\frac{\partial}{\partial x} (x^{a} b^{b})

Treat

a, b

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b^{b} \frac{\partial}{\partial x} (x^{a})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= b^{b} a x^{a - 1}

\int \frac{x}{4 + 9 x ^{2}} d x

t \to 3 lim (\frac{\frac{1}{t} - \frac{1}{3}}{t - 3})

\int 4000 x e^{- 0.2 x} d x

\frac{d}{d x} (4 π x^{2})

x \to - 2 lim (2)

What is (\partial)/(\partial x)(x^ab^b) ?
The answer to (\partial)/(\partial x)(x^ab^b) is b^bax^{a-1}