What is the integral of (sin^3(x)) ?

The integral of (sin^3(x)) is -cos(x)+(cos^3(x))/3+C

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integral of (sin^3(x))

\int (sin^{3} (x)) d x

- cos (x) + \frac{cos ^{3} ( x )}{3} + C

Solution steps

\int sin^{3} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x)) sin (x) d x

Apply u-substitution

: \int - 1 + u^{2} d u

= \int - 1 + u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d u + \int u^{2} d u

\int 1 d u = u

\int u^{2} d u = \frac{u ^{3}}{3}

= - u + \frac{u ^{3}}{3}

Substitute back

u = cos (x)

= - cos (x) + \frac{cos ^{3} ( x )}{3}

Add a constant to the solution

= - cos (x) + \frac{cos ^{3} ( x )}{3} + C

f (x) = 4 x^{3} - 4 x, at x = 1

\frac{d}{d t} (t^{2} + 5 t)

\frac{\partial}{\partial t} (ln (k x - m t))

f (x) = \frac{x ^{2} - 1}{x ^{2} + 1}

\frac{d}{d x} (\frac{4 x}{9 y})

What is the integral of (sin^3(x)) ?
The integral of (sin^3(x)) is -cos(x)+(cos^3(x))/3+C