What is the limit as x approaches 5 of (x+1)/(x-5) ?

The limit as x approaches 5 of (x+1)/(x-5) is diverges

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limit as x approaches 5 of (x+1)/(x-5)

x \to 5 lim (\frac{x + 1}{x - 5})

diverges

Solution steps

x \to 5 lim (\frac{x + 1}{x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 5 + lim (\frac{x + 1}{x - 5}) = \infty

x \to 5 - lim (\frac{x + 1}{x - 5}) = - \infty

= diverges

(x^{2} - 8)^{4}, at x = 3

f (x) = 7 + 4 x^{2} - 2 x^{3}, at x = 1

\frac{d}{d x} (c e^{x} + c e^{- x})

\frac{d}{d x} (\frac{x}{x - 1})

\int x^{3} (1 + 9 x^{4}) d x

What is the limit as x approaches 5 of (x+1)/(x-5) ?
The limit as x approaches 5 of (x+1)/(x-5) is diverges