What is the derivative of 4cos(4x) ?

The derivative of 4cos(4x) is -16sin(4x)

What is the first derivative of 4cos(4x) ?

The first derivative of 4cos(4x) is -16sin(4x)

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\frac{d}{d x} (4 cos (4 x))

- 16 sin (4 x)

Solution steps

\frac{d}{d x} (4 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 4 (- sin (4 x) \cdot 4)

Simplify

= - 16 sin (4 x)

f^{^{'}} (x) = 3 x - 4, f (- 1) = \frac{13}{2}

ln (196 sin^{2} (x))

\int \frac{1}{5 - 7 x} d x

y^{^{''''}} + 4 y^{^{''}} + 4 y = 0

\frac{\partial}{\partial x} (2 x y^{2} - 2 x^{3} y)

What is the derivative of 4cos(4x) ?
The derivative of 4cos(4x) is -16sin(4x)
What is the first derivative of 4cos(4x) ?
The first derivative of 4cos(4x) is -16sin(4x)