What is the tangent of f(x)=12sqrt(x)-2x,\at x=9 ?

The tangent of f(x)=12sqrt(x)-2x,\at x=9 is y=18

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tangent of f(x)=12sqrt(x)-2x,\at x=9

tangent of

f (x) = 12 x - 2 x, at x = 9

y = 18

Solution steps

Find the tangent point:

(9, 18)

Find the slope of

f (x) = 12 x - 2 x : \frac{df ( x )}{d x} = \frac{6}{x} - 2

Compute the slope of

f (x) = 12 x - 2 x

x = 9 : m = 0

Find the line with slope m=

0

and passing through

(9, 18) : y = 18

y = 18

\int \frac{3}{9 + x ^{2}} d x

e^{s i n (2 x)}

\int - 2 cos (x) + 3 x^{2} - 5 x + 4 d x

\int 3 x + \frac{1}{3 x} d x

y^{^{''}} - 6 y^{^{'}} + 7 y = 0, y (0) = 0, y^{^{'}} (0) = 7

What is the tangent of f(x)=12sqrt(x)-2x,\at x=9 ?
The tangent of f(x)=12sqrt(x)-2x,\at x=9 is y=18