What is the derivative of 3e^{3e^x+x} ?

The derivative of 3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)

What is the first derivative of 3e^{3e^x+x} ?

The first derivative of 3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)

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derivative of

3 e^{3 e^{x} + x}

3 e^{3 e^{x} + x} (3 e^{x} + 1)

Solution steps

\frac{d}{d x} (3 e^{3 e^{x} + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{3 e^{x} + x})

Apply the chain rule:

e^{3 e^{x} + x} \frac{d}{d x} (3 e^{x} + x)

= e^{3 e^{x} + x} \frac{d}{d x} (3 e^{x} + x)

\frac{d}{d x} (3 e^{x} + x) = 3 e^{x} + 1

= 3 e^{3 e^{x} + x} (3 e^{x} + 1)

\int (e - x - e^{3}) (e x + e - 5) d x

\int_{9}^{x} 1 + 9 t d t

\int sec^{4} (3 x) tan^{2} (3 x) d x

\frac{d}{d x} (lo g_{e} (x^{3}))

\int_{0}^{2} \frac{1}{8} (x + y) d y

What is the derivative of 3e^{3e^x+x} ?
The derivative of 3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)
What is the first derivative of 3e^{3e^x+x} ?
The first derivative of 3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)