What is the integral of (sin(x)-7cos(x)) ?

The integral of (sin(x)-7cos(x)) is -cos(x)-7sin(x)+C

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integral of (sin(x)-7cos(x))

\int (sin (x) - 7 cos (x)) d x

- cos (x) - 7 sin (x) + C

Solution steps

\int sin (x) - 7 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (x) d x - \int 7 cos (x) d x

\int sin (x) d x = - cos (x)

\int 7 cos (x) d x = 7 sin (x)

= - cos (x) - 7 sin (x)

Add a constant to the solution

= - cos (x) - 7 sin (x) + C

\int 2 ∣ x ∣ d x

\int \frac{e ^{x}}{e ^{2 x} + 9} d x

\int 7 sin^{4} (x co) s^{2} x d x

x \to \infty lim (1.0 3^{x})

y^{^{''}} + π^{2} y = 0

What is the integral of (sin(x)-7cos(x)) ?
The integral of (sin(x)-7cos(x)) is -cos(x)-7sin(x)+C