What is the integral of 1/(6x+5) ?

The integral of 1/(6x+5) is 1/6 ln|6x+5|+C

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integral of 1/(6x+5)

\int \frac{1}{6 x + 5} d x

\frac{1}{6} ln ∣ 6 x + 5 ∣ + C

Solution steps

\int \frac{1}{6 x + 5} d x

Apply u-substitution

: \int \frac{1}{6 u} d u

= \int \frac{1}{6 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{6} ln ∣ u ∣

Substitute back

u = 6 x + 5

= \frac{1}{6} ln ∣ 6 x + 5 ∣

Add a constant to the solution

= \frac{1}{6} ln ∣ 6 x + 5 ∣ + C

\int 3 x + 3 d x

(y^{4} - x^{2}) (\frac{d y}{d x}) = - x y

\frac{d y}{d t} = 0.5 - t + 2 y

x \to 0 lim ((\frac{e}{x})^{x})

y \frac{d y}{d x} = 2 x e^{y^{2}}