What is the derivative of (3x^6+4x^3)^4 ?

The derivative of (3x^6+4x^3)^4 is 4(3x^6+4x^3)^3(18x^5+12x^2)

What is the first derivative of (3x^6+4x^3)^4 ?

The first derivative of (3x^6+4x^3)^4 is 4(3x^6+4x^3)^3(18x^5+12x^2)

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derivative of

(3 x^{6} + 4 x^{3})^{4}

4 (3 x^{6} + 4 x^{3})^{3} (18 x^{5} + 12 x^{2})

Solution steps

\frac{d}{d x} ((3 x^{6} + 4 x^{3})^{4})

Apply the chain rule:

4 (3 x^{6} + 4 x^{3})^{3} \frac{d}{d x} (3 x^{6} + 4 x^{3})

= 4 (3 x^{6} + 4 x^{3})^{3} \frac{d}{d x} (3 x^{6} + 4 x^{3})

\frac{d}{d x} (3 x^{6} + 4 x^{3}) = 18 x^{5} + 12 x^{2}

= 4 (3 x^{6} + 4 x^{3})^{3} (18 x^{5} + 12 x^{2})

\int_{- \infty}^{1} - e^{x} d x

\int (\frac{r}{3}) cos (\frac{r}{3}) d r

\frac{6 ( s + 1 )}{s ^{2} ( s + 1 )}

\frac{\partial}{\partial x} (arcsin (2 x))

\int (x y) d x

What is the derivative of (3x^6+4x^3)^4 ?
The derivative of (3x^6+4x^3)^4 is 4(3x^6+4x^3)^3(18x^5+12x^2)
What is the first derivative of (3x^6+4x^3)^4 ?
The first derivative of (3x^6+4x^3)^4 is 4(3x^6+4x^3)^3(18x^5+12x^2)