en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (4y)/1

Solution

\int \frac{4 y}{1} d y

Solution

2 y^{2} + C

Solution steps

\int \frac{4 y}{1} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int y d y

Apply the Power Rule

: \frac{y ^{2}}{2}

= 4 \cdot \frac{y ^{2}}{2}

Simplify

4 \cdot \frac{y ^{2}}{2} : 2 y^{2}

= 2 y^{2}

Add a constant to the solution

= 2 y^{2} + C

Popular Examples

tangent of y=2e^xcos(x),(0,2)tangent of

y = 2 e^{x} cos (x), (0, 2)

integral of x^pi

\int x^{π} d x

integral of 2sqrt(x)+3

\int 2 x + 3 d x

limit as x approaches 0 of x^{x^x}-1

x \to 0 lim (x^{x^{x}} - 1)

derivative of (x^2)/3+1/(x^2)derivative of

\frac{x ^{2}}{3} + \frac{1}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the integral of (4y)/1 ?
The integral of (4y)/1 is 2y^2+C