What is the limit as x approaches pi of 1/(sin(x)) ?

The limit as x approaches pi of 1/(sin(x)) is diverges

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limit as x approaches pi of 1/(sin(x))

x \to π lim (\frac{1}{sin ( x )})

diverges

Solution steps

x \to π lim (\frac{1}{sin ( x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to π + lim (\frac{1}{sin ( x )}) = - \infty

x \to π - lim (\frac{1}{sin ( x )}) = \infty

= diverges

\int \frac{x ^{2}}{( 1 - 16 x ^{2} ) ^{\frac{3}{2}}} d x

x \to 5 - lim (5 - x)

\int \frac{x ^{5} + 7}{x ^{2}} d x

h^{^{''}} = 40 + 4 t

\frac{d}{d x} (\frac{1}{4 + x ^{2}})

What is the limit as x approaches pi of 1/(sin(x)) ?
The limit as x approaches pi of 1/(sin(x)) is diverges