What is the limit as x approaches infinity of sin(((2x-1)pi)/2) ?

The limit as x approaches infinity of sin(((2x-1)pi)/2) is diverges

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limit as x approaches infinity of sin(((2x-1)pi)/2)

x \to \infty lim (sin (\frac{( 2 x - 1 ) π}{2}))

diverges

Solution steps

x \to \infty lim (sin (\frac{( 2 x - 1 ) π}{2}))

Apply Limit Divergence Criterion:

diverges

= diverges

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What is the limit as x approaches infinity of sin(((2x-1)pi)/2) ?
The limit as x approaches infinity of sin(((2x-1)pi)/2) is diverges