What is the integral from 0 to 2 of x/8 ?

The integral from 0 to 2 of x/8 is 1/4

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integral from 0 to 2 of x/8

\int_{0}^{2} \frac{x}{8} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{0}^{2} \frac{x}{8} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= \frac{1}{8} [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= \frac{1}{8} \cdot 2

Simplify

= \frac{1}{4}

\frac{\partial}{\partial y} (2 x - x^{3} + 3 x y^{2})

y^{2} (\frac{d x}{d y}) + y^{3} = 1

\int \frac{x ^{2}}{x ^{2} + 1} d x

7 x e^{x}

\int cos (8 x) cos (5 x) d x

What is the integral from 0 to 2 of x/8 ?
The integral from 0 to 2 of x/8 is 1/4