What is the derivative of y=\sqrt[5]{x} ?

The derivative of y=\sqrt[5]{x} is 1/(5x^{4/5)}

What is the first derivative of y=\sqrt[5]{x} ?

The first derivative of y=\sqrt[5]{x} is 1/(5x^{4/5)}

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derivative of

\frac{1}{5 x ^{\frac{4}{5}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{5} x^{\frac{1}{5} - 1}

Simplify

\frac{1}{5} x^{\frac{1}{5} - 1} : \frac{1}{5 x ^{\frac{4}{5}}}

= \frac{1}{5 x ^{\frac{4}{5}}}

\int sin (7 x) d x

y^{^{''}} + 4 y = 4 t

f (x) = (7^{- 3 x})

\int (4 x^{2} - \frac{2}{x}) d x

What is the derivative of y=\sqrt[5]{x} ?
The derivative of y=\sqrt[5]{x} is 1/(5x^{4/5)}
What is the first derivative of y=\sqrt[5]{x} ?
The first derivative of y=\sqrt[5]{x} is 1/(5x^{4/5)}