What is the limit as x approaches 0+of x*ln(x^4) ?

The limit as x approaches 0+of x*ln(x^4) is 0

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limit as x approaches 0+of x*ln(x^4)

x \to 0 + lim (x \cdot ln (x^{4}))

0

Solution steps

x \to 0 + lim (x ln (x^{4}))

ln (x^{4}) = 4 ln (x)

= x \to 0 + lim (x \cdot 4 ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 4 \cdot x \to 0 + lim (x ln (x))

Rewrite for L'Hopital

= 4 \cdot x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}})

= 4 \cdot x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}})

Simplify

\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}} : - x

= 4 \cdot x \to 0 + lim (- x)

Plug in the value

x = 0

= 4 (- 0)

Simplify

= 0

\int \frac{1}{x ^{2} ( x ^{2} - 9 )} d x

\int (\frac{1}{x ( 2 x ^{2} - x + 1 ) ( x + 1 )}) d x

(1, 2), (- 1, - 2)

y = x + x, (1, 2)

\frac{d}{d x} (\frac{8 x ^{2} + 6 x + 4}{x})

What is the limit as x approaches 0+of x*ln(x^4) ?
The limit as x approaches 0+of x*ln(x^4) is 0