What is the solution for (5x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 ?

The solution for (5x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 is y=ln(5ln(x)+c_{1})x

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(5x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4

(5 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 4

y = ln (5 ln (x) + c_{1}) x

Solution steps

(5 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (5 ln (x) + c_{1}) x

y = ln (5 ln (x) + c_{1}) x

\int_{0}^{6} (x^{2} - 4) d x

y^{^{'}} + 2 x y = x^{2}

f (x) = \frac{4 x ^{3} - 2 x + 1}{x ^{2}}

x \to + 6 lim (3)

\int x (1 - x)^{2} d x

What is the solution for (5x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 ?
The solution for (5x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 is y=ln(5ln(x)+c_{1})x