What is area y=e^x,y=e^{-3x},x=ln(4) ?

The answer to area y=e^x,y=e^{-3x},x=ln(4) is 171/64

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area y=e^x,y=e^{-3x},x=ln(4)

area

y = e^{x}, y = e^{- 3 x}, x = ln (4)

\frac{171}{64}

Decimal Notation

2.671875

Solution steps

Apply the area formula:

\int_{0}^{l n (4)} e^{x} - e^{- 3 x} d x

Solve

\int_{0}^{l n (4)} e^{x} - e^{- 3 x} d x : \frac{171}{64}

The area is:

= \frac{171}{64}

7 - 2 x

x \to - 1 lim ((x + 3 x^{4})^{3})

\frac{d}{d x} (6^{(4 - 3 x)})

\int_{1}^{4} (x^{2} - 3 x) d x

\frac{d}{d θ} (2 sin (3 θ))

What is area y=e^x,y=e^{-3x},x=ln(4) ?
The answer to area y=e^x,y=e^{-3x},x=ln(4) is 171/64