What is the limit as x approaches 0 of ((x+2)^2-8)/x ?

The limit as x approaches 0 of ((x+2)^2-8)/x is diverges

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limit as x approaches 0 of ((x+2)^2-8)/x

x \to 0 lim (\frac{( x + 2 ) ^{2} - 8}{x})

diverges

Solution steps

x \to 0 lim (\frac{( x + 2 ) ^{2} - 8}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{( x + 2 ) ^{2} - 8}{x}) = - \infty

x \to 0 - lim (\frac{( x + 2 ) ^{2} - 8}{x}) = \infty

= diverges

x^{2} + 8 x - 3, - x^{2} + 4 x + 3

n = 1 \sum \infty \frac{5 ^{n}}{9}

f (x) = \frac{sin ( 4 x )}{sin ( 5 x )}

y = arctan (3 x^{2})

\int e^{10 t} d t

What is the limit as x approaches 0 of ((x+2)^2-8)/x ?
The limit as x approaches 0 of ((x+2)^2-8)/x is diverges