What is the tangent of y=2x^2-13x+3 ?

The tangent of y=2x^2-13x+3 is y=(4a_{0}-13)x-2a_{0}^2+3

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tangent of y=2x^2-13x+3

tangent of

y = 2 x^{2} - 13 x + 3

y = (4 a_{0} - 13) x - 2 a_{0}^{2} + 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 13 a_{0} + 3)

Find the slope of

y = 2 x^{2} - 13 x + 3 : \frac{d y}{d x} = 4 x - 13

Compute the slope of

y = 2 x^{2} - 13 x + 3

x = a_{0} : m = 4 a_{0} - 13

Find the line with slope m=

4 a_{0} - 13

and passing through

(a_{0}, 2 a_{0}^{2} - 13 a_{0} + 3) : y = (4 a_{0} - 13) x - 2 a_{0}^{2} + 3

y = (4 a_{0} - 13) x - 2 a_{0}^{2} + 3

\int x^{2} 2^{x^{3} + 1} d x

\int u^{- 2} d u

\int (x^{2} + 4)^{7} 2 x d x

\frac{d}{d x} (sin (π x + 1))

\frac{d}{d x} (tan (x^{3} + 3))

What is the tangent of y=2x^2-13x+3 ?
The tangent of y=2x^2-13x+3 is y=(4a_{0}-13)x-2a_{0}^2+3