What is the integral from 0 to 2pi of integral of 1 ?

The integral from 0 to 2pi of integral of 1 is 2pi(x+C)

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integral from 0 to 2pi of integral of 1

\int_{0}^{2 π} \int 1 d x d y

2 π (x + C)

Solution steps

\int_{0}^{2 π} \int 1 d x d y

\int 1 d x = x + C

= \int_{0}^{2 π} (x + C) d y

\int_{0}^{2 π} (x + C) d y = 2 π (x + C)

= 2 π (x + C)

\frac{\partial}{\partial z} (z^{3})

x \to - 9 lim (5 x)

x \to 0 lim (\frac{- 1}{x ^{2}})

\frac{\partial}{\partial x} (4 x^{2} y + 2 x y^{2})

sin (cos (x))

What is the integral from 0 to 2pi of integral of 1 ?
The integral from 0 to 2pi of integral of 1 is 2pi(x+C)