What is the tangent of y=sin(sin(x)),(4pi,0) ?

The tangent of y=sin(sin(x)),(4pi,0) is y=x-4pi

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tangent of y=sin(sin(x)),(4pi,0)

tangent of

y = sin (sin (x)), (4 π, 0)

y = x - 4 π

Solution steps

Find the slope of

y = sin (sin (x)) : \frac{d y}{d x} = cos (sin (x)) cos (x)

Compute the slope of

y = sin (sin (x))

(4 π, 0) : m = 1

Find the line with slope m=

1

and passing through

(4 π, 0) : y = x - 4 π

y = x - 4 π

\frac{d}{d x} (3 x^{2} - 15)

n = 1 \sum \infty \frac{n}{n + 6}

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

\int \frac{1}{x ^{11}} d x

x y^{2} (x \frac{d y}{d x} + y) = 9

What is the tangent of y=sin(sin(x)),(4pi,0) ?
The tangent of y=sin(sin(x)),(4pi,0) is y=x-4pi