What is the first derivative of 6-2x ?

The first derivative of 6-2x is -2

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derivative of 6-2x

\frac{d}{d x} (6 - 2 x)

- 2

Solution steps

\frac{d}{d x} (6 - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6) - \frac{d}{d x} (2 x)

\frac{d}{d x} (6) = 0

\frac{d}{d x} (2 x) = 2

= 0 - 2

Simplify

= - 2

\int sin^{3} (θ) d θ

\frac{\partial}{\partial u} (\frac{u + v}{3})

49 y^{^{''}} + 126 y^{^{'}} + 81 y = 0

\int_{0}^{\frac{π}{3}} tan^{3} (x) d x