What is the solution for (x+y)dx+xln(x)dy=0 ?

The solution for (x+y)dx+xln(x)dy=0 is y=-x/(ln(x))+(c_{1})/(ln(x))

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(x+y)dx+xln(x)dy=0

(x + y) d x + x ln (x) d y = 0

y = - \frac{x}{ln ( x )} + \frac{c _{1}}{ln ( x )}

Solution steps

(x + y) d x + x ln (x) d y = 0

Solve linear ODE:

y = - \frac{x}{ln ( x )} + \frac{c _{1}}{ln ( x )}

y = - \frac{x}{ln ( x )} + \frac{c _{1}}{ln ( x )}

\frac{\partial}{\partial y} (x e^{x y})

x \to 7 lim (tan (\frac{π x}{6}))

f (x) = 3 + 4 x^{2} - 2 x^{3}, (1, 5)

\frac{d ^{3} x}{d t ^{3}} = 4 t^{3} + t

\frac{d}{d x} (\frac{2 x ^{2} + 1}{x})

What is the solution for (x+y)dx+xln(x)dy=0 ?
The solution for (x+y)dx+xln(x)dy=0 is y=-x/(ln(x))+(c_{1})/(ln(x))