What is (\partial)/(\partial x)(21xye^{-x^2-y^2}) ?

The answer to (\partial)/(\partial x)(21xye^{-x^2-y^2}) is 21y(e^{-x^2-y^2}-2e^{-x^2-y^2}x^2)

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(\partial)/(\partial x)(21xye^{-x^2-y^2})

\frac{\partial}{\partial x} (21 x y e^{- x^{2} - y^{2}})

21 y (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

Solution steps

\frac{\partial}{\partial x} (21 x y e^{- x^{2} - y^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 21 y \frac{\partial}{\partial x} (x e^{- x^{2} - y^{2}})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x^{2} - y^{2}}

= 21 y (\frac{\partial}{\partial x} (x) e^{- x^{2} - y^{2}} + \frac{\partial}{\partial x} (e^{- x^{2} - y^{2}}) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{- x^{2} - y^{2}}) = - 2 e^{- x^{2} - y^{2}} x

= 21 y (1 \cdot e^{- x^{2} - y^{2}} + (- 2 e^{- x^{2} - y^{2}} x) x)

Simplify

21 y (1 \cdot e^{- x^{2} - y^{2}} + (- 2 e^{- x^{2} - y^{2}} x) x) : 21 y (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

= 21 y (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

\int e^{5 x} e^{5 x} + 4 d x

f (x) = (x + \frac{1}{x}) (2 - x^{2})

\int \frac{tan ^{5} ( x )}{sec ( x )} d x

\frac{d}{d x} ((4 x - 1)^{3} (5 x + 3)^{2})

\int \frac{1}{( 1 + cos ^{2} ( x ) )} d x

What is (\partial)/(\partial x)(21xye^{-x^2-y^2}) ?
The answer to (\partial)/(\partial x)(21xye^{-x^2-y^2}) is 21y(e^{-x^2-y^2}-2e^{-x^2-y^2}x^2)