What is (\partial)/(\partial x)(sqrt(8-x^2-3y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(8-x^2-3y^2)) is -x/(sqrt(8-x^2-3y^2))

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(\partial)/(\partial x)(sqrt(8-x^2-3y^2))

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

- \frac{x}{8 - x ^{2} - 3 y ^{2}}

Solution steps

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 8 - x ^{2} - 3 y ^{2}} \frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

= \frac{1}{2 8 - x ^{2} - 3 y ^{2}} \frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2}) = - 2 x

= \frac{1}{2 8 - x ^{2} - 3 y ^{2}} (- 2 x)

Simplify

\frac{1}{2 8 - x ^{2} - 3 y ^{2}} (- 2 x) : - \frac{x}{8 - x ^{2} - 3 y ^{2}}

= - \frac{x}{8 - x ^{2} - 3 y ^{2}}

\int (2 t + 1) e^{t^{2} + t} d t

\frac{d}{d x} (ln (5 x^{2} - 3 x + 4))

\frac{ln ( x )}{x ^{4}}

\int \frac{x}{x - 36} d x

y = 4 x - x^{2}

What is (\partial)/(\partial x)(sqrt(8-x^2-3y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(8-x^2-3y^2)) is -x/(sqrt(8-x^2-3y^2))