What is the integral of y/((y+5)(2y-1)) ?

The integral of y/((y+5)(2y-1)) is 5/11 ln|y+5|+1/22 ln|2y-1|+C

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integral of y/((y+5)(2y-1))

\int \frac{y}{( y + 5 ) ( 2 y - 1 )} d y

\frac{5}{11} ln ∣ y + 5 ∣ + \frac{1}{22} ln ∣ 2 y - 1 ∣ + C

Solution steps

\int \frac{y}{( y + 5 ) ( 2 y - 1 )} d y

Take the partial fraction of

\frac{y}{( y + 5 ) ( 2 y - 1 )} : \frac{5}{11 ( y + 5 )} + \frac{1}{11 ( 2 y - 1 )}

= \int \frac{5}{11 ( y + 5 )} + \frac{1}{11 ( 2 y - 1 )} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{5}{11 ( y + 5 )} d y + \int \frac{1}{11 ( 2 y - 1 )} d y

\int \frac{5}{11 ( y + 5 )} d y = \frac{5}{11} ln ∣ y + 5 ∣

\int \frac{1}{11 ( 2 y - 1 )} d y = \frac{1}{22} ln ∣ 2 y - 1 ∣

= \frac{5}{11} ln ∣ y + 5 ∣ + \frac{1}{22} ln ∣ 2 y - 1 ∣

Add a constant to the solution

= \frac{5}{11} ln ∣ y + 5 ∣ + \frac{1}{22} ln ∣ 2 y - 1 ∣ + C

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What is the integral of y/((y+5)(2y-1)) ?
The integral of y/((y+5)(2y-1)) is 5/11 ln|y+5|+1/22 ln|2y-1|+C